2x^2+61x=330

Solution for 2x^2+61x=330 equation:

2x^2+61x=330

We move all terms to the left:

2x^2+61x-(330)=0

a = 2; b = 61; c = -330;
Δ = b2-4ac
Δ = 612-4·2·(-330)
Δ = 6361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{6361}}{2*2}=\frac{-61-\sqrt{6361}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{6361}}{2*2}=\frac{-61+\sqrt{6361}}{4}
$